소개글
[화학공정] 화공양론 문제풀이-Problem 6. 81에 대한 자료입니다.
목차
1.Problem
2.How ?
3.Solution (a)
4.Solution (b)
본문내용
Q = (360gmol/s)X(0.040kJ/gmol·s)X(1400°C−900°C)
= 7200kJ/s
Heat exchanger cool that gas to 25℃, and it condense water.
Q1=(9.5gmol/s)(29.1kJ/gmol)+(9.5gmol/s)(24.1kJ/gmol)
+(90.5gmol/s)(-22.9kJ/gmol)
+ (20.5gmol/s)(-37.4kJ/gmol)
= - 3344kJ/s
Q2(latent heat of water) =(9.5gmol/s)(-40kJ/gmol)
= - 380kJ/s
Q1+Q2 = - 3704kJ/s
The heat removal rate in the exchanger(-3724kJ/s) is less than the heat addition rate in the reactor, because the net reaction is endothermic.